去括号(4x-3y)-[-(3-x)+(x-y)]-5x 还是去括号4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}

来源：学生作业帮助网编辑：作业帮时间：2024/04/29 07:52:49

去括号(4x-3y)-[-(3-x)+(x-y)]-5x 还是去括号4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}
去括号(4x-3y)-[-(3-x)+(x-y)]-5x 还是去括号4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}

去括号(4x-3y)-[-(3-x)+(x-y)]-5x 还是去括号4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}
4x-3y-[-3+x+x-y]-5x
=4x-3y+3-2x+y-5x
=-3x-2y+3
去括号先从里面去后依次向外一样的要合并
4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}
=4xy²-3x²y-3x²-xy²+[2xy²-4x²y+(x²y-2xy²)]}
=4xy²-3x²y-3x²-xy²+2xy²-4x²y+x²y-2xy²
=3xy²-6x²y-3x²

(4x-3y)-[-(3-x)+(x-y)]-5x=(4x-3y)+(3-x)-(x-y)-5x=4x-3y+3-x-x+y-5x=3-2y-3x
4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}=4xy²-3x²y-3x²-xy²+[...

全部展开

(4x-3y)-[-(3-x)+(x-y)]-5x=(4x-3y)+(3-x)-(x-y)-5x=4x-3y+3-x-x+y-5x=3-2y-3x
4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}=4xy²-3x²y-3x²-xy²+[2xy²-4x²y+(x²y-2xy²)]}=4xy²-3x²y-3x²-xy²+2xy²-4x²y+x²y-2xy²=3xy²-6x²y-3x²

收起

小兄弟, 这种题考得是负负得正的问题, 这个问题记住了, 就会解了.

(4x-3y)-[-(3-x)+(x-y)]-5x
=4x-3y+(3-x)-(x-y)-5x
=4x-3y+3-x-x+y-5x
=-3x-2y+3
4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]}
=4xy^2-3x^2y-[3x^2+xy^2-(2xy^2-4x^2y+x^2y-2xy^2)]
=4xy^2-3x^2y-(3x^2+xy^2+3x^2y)
=4xy^2-3x^2y-3x^2-xy^2-3x^2y
=3xy^2-6x^2y-3x^2

3x-【(y-x)-2x-y】去括号, (3+x)(3+y)去括号 3(x+y)平方怎么去括号 3(x-y)平方怎么去括号 —[—(3x-y)]去括号. —[—(3x-y)]去括号. 去括号x-3(y-1) 3x-2y-[-4x+(x+3y)]+y 去括号然后合并同类项, (2x-3y)-(5x-y)去括号 (2x+3y)-(5x-y)去括号去括号3（x-y)-2(2x-y)= 3(x-4) 去括号 3x-(3x+4y)+(4x+2y)去括号,并合并同类项 x+(-y+3) x-(-3-y) -(x-y)+3 3-(X+Y) 怎样去括号?快去括号(4x-3y)-[-(3-x)+(x-y)]-5x 还是去括号4xy²-3x²y-{3x²+xy²-[2xy²-4x²y+(x²y-2xy²)]} 5（2x-7y)-3(4x-10y) 去括号,再合并同类项, 去括号 5（2x-7y）-3（4x-10y）整体去括号；化简[5(x-y)-3(x-y)-(x-y)+2(x-y)]-2(x-y)