作业帮Mathematica解三次二元带参数的方程Solve[{-3*x + a*Sqrt[1.5]*y^2 + 1.5*x*(2*x^2 + r*(1 - x^2 - y^2)) == 0,-a*Sqrt[1.5]*x*y + 1.5*y*(2*x^2 + r*(1 - x^2 - y^2)) == 0},{x,y}]——————————————这个方程解了以后,发
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/10 22:28:16
![Mathematica解三次二元带参数的方程Solve[{-3*x + a*Sqrt[1.5]*y^2 + 1.5*x*(2*x^2 + r*(1 - x^2 - y^2)) == 0,-a*Sqrt[1.5]*x*y + 1.5*y*(2*x^2 + r*(1 - x^2 - y^2)) == 0},{x,y}]——————————————这个方程解了以后,发](/uploads/image/z/4728215-47-5.jpg?t=Mathematica%E8%A7%A3%E4%B8%89%E6%AC%A1%E4%BA%8C%E5%85%83%E5%B8%A6%E5%8F%82%E6%95%B0%E7%9A%84%E6%96%B9%E7%A8%8BSolve%5B%7B-3%2Ax+%2B+a%2ASqrt%5B1.5%5D%2Ay%5E2+%2B+1.5%2Ax%2A%282%2Ax%5E2+%2B+r%2A%281+-+x%5E2+-+y%5E2%29%29+%3D%3D+0%2C-a%2ASqrt%5B1.5%5D%2Ax%2Ay+%2B+1.5%2Ay%2A%282%2Ax%5E2+%2B+r%2A%281+-+x%5E2+-+y%5E2%29%29+%3D%3D+0%7D%2C%7Bx%2Cy%7D%5D%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E2%80%94%E8%BF%99%E4%B8%AA%E6%96%B9%E7%A8%8B%E8%A7%A3%E4%BA%86%E4%BB%A5%E5%90%8E%2C%E5%8F%91)
Mathematica解三次二元带参数的方程Solve[{-3*x + a*Sqrt[1.5]*y^2 + 1.5*x*(2*x^2 + r*(1 - x^2 - y^2)) == 0,-a*Sqrt[1.5]*x*y + 1.5*y*(2*x^2 + r*(1 - x^2 - y^2)) == 0},{x,y}]——————————————这个方程解了以后,发
Mathematica解三次二元带参数的方程
Solve[{-3*x + a*Sqrt[1.5]*y^2 + 1.5*x*(2*x^2 + r*(1 - x^2 - y^2)) ==
0,-a*Sqrt[1.5]*x*y + 1.5*y*(2*x^2 + r*(1 - x^2 - y^2)) == 0},{x,
y}]
——————————————
这个方程解了以后,发现不是我想要的结果.谁能把x,y表示成a,r的形式?
Mathematica解三次二元带参数的方程Solve[{-3*x + a*Sqrt[1.5]*y^2 + 1.5*x*(2*x^2 + r*(1 - x^2 - y^2)) == 0,-a*Sqrt[1.5]*x*y + 1.5*y*(2*x^2 + r*(1 - x^2 - y^2)) == 0},{x,y}]——————————————这个方程解了以后,发
你只需将所有的1.5改成3/2即可.3/2是一个精确数字.而1.5系统认为是近似数.
In[1]:= r =.;
a =.; Solve[{-3*x + a*Sqrt[3/2]*y^2 +
3/2*x*(2*x^2 + r*(1 - x^2 - y^2)) ==
0,-a*Sqrt[3/2]*x*y + 3/2*y*(2*x^2 + r*(1 - x^2 - y^2)) == 0},{x,
y}]
Out[2]= {{y -> 0,x -> -1},{y -> 0,x -> 0},{y -> 0,
x -> 1},{y -> -(Sqrt[6 - a^2]/Sqrt[6]),
x -> a/Sqrt[6]},{y -> Sqrt[6 - a^2]/Sqrt[6],
x -> a/Sqrt[6]},{y -> -Sqrt[(3/2)] Sqrt[(2 r)/a^2 - r^2/a^2],
x -> (Sqrt[3/2] r)/a},{y -> Sqrt[3/2] Sqrt[(2 r)/a^2 - r^2/a^2],
x -> (Sqrt[3/2] r)/a}}