若2sinx+3cosx=0,则(sin^2x+sin2x)/(cos^2x)

来源：学生作业帮助网编辑：作业帮时间：2024/04/29 17:43:48

若2sinx+3cosx=0,则(sin^2x+sin2x)/(cos^2x)
若2sinx+3cosx=0,则(sin^2x+sin2x)/(cos^2x)

若2sinx+3cosx=0,则(sin^2x+sin2x)/(cos^2x)
2sinx+3cosx=0
sinx/cosx=-3/2=tanx
(sin^2x+sin2x)/(cos^2x)
=(sin^2x+2sinxcosx)/(cos^2x) (上下同除以cos^2x)
=(tan^2x+2tanx)
=9/4-3
=-3/4

2sinx+3cosx=0
2sinx=-3cosx sinx=-3/2cosx
(sin^2x+sin2x)/(cos^2x)
=(sin^2x+2sinxcosx)/(cos^2x)
=(9/4cos^2x-3cos^2x)/(cos^2x)
=9/4-3
=-3/4

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