函数y=cos(2x+π/4) 求dy
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函数y=cos(2x+π/4) 求dy
函数y=cos(2x+π/4) 求dy
函数y=cos(2x+π/4) 求dy
dy=-sin(2x+π/4)*(2x+π/4)'dx
=-2sin(2x+π/4)dx
dy是啥
dy=y'*dx=-2sin(2x+π/4)*dx
dy= -2sin(2x+TT/4)
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