若lim[(an^2+bn+c)/(2n-3)]=-2,则a+b=

若lim[(an^2+bn+c)/(2n-3)]=-2,则a+b= 已知lim n→∞an^2+cn/bn^2+c=2,lim n→∞bn+c/cn+a=3,则lim n→∞an^2+bn+c/cn^2+an+b的值是 已知a,b,c是实数,若极限lim n→∞(an+c/bn-2c)=2,lim n→∞(bn^2-c/cn^2-b)=3,则 lim n→∞(an^3+bn^2+c/cn^3+an^2+bn)的值为 lim(5n-根号（an^2+bn+c)）=2,求实数a,b,c lim(n→∞) an=2,lim(n→∞) bn=1,求lim(n→∞) （an-bn）/（an+bn） 等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn 对于数列an、bn,若lim(3an-2bn)=6,lim(an+bn)=2,求lim(4an+3bn) 若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5求常数a、b、c lim(3an+4bn)=8 lim(6an-bn)=1 求lim(3an+bn) 要设3an+4bn=m 6an-bn=t第二题若an=(5-3x）^n 1)an存在极限,求x范围 2）an极限为零 求x范围 An=1/n^2 Bn=A1+A2.+An lim Bn=?n趋于无穷求lim(n→∞) Bn lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b写出过程． 已知[5n-√(an^2-bn+c)]的极限是2,求a、b、c的值.(a,b已求出)如下 c怎么求,但是C属于R由原式,得lim(5n)-lim√(an²-bn+c)=2lim(5n-2)=lim√(an²-bn+c)根据极限的唯一性,得5n-2=√(an²-bn+c)即：(5n-2)²=a lim(2an+4bn)=1 lim(3an-bn)=2 求lim(an+bn) lim(2an+4bn)=1 lim(3an-bn)=2 求lim(an+bn) 若(1+5X2)n的展开式中各项系数之和是an,(2X3+5)n展开式中各项二项式系数之和为bn,求lim(an-2bn/3an+4bn),n趋近于无穷的值. 若lim(2n+(an^2-2n+1)/(bn+2))=1 求a/b的值 极限基础题 求步骤~~~若lim(an+(n^2+bn-2)/(n-1))=2 则a+b=