(a+1)x^2-2a^2x+a^3=0

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(a+1)x^2-2a^2x+a^3=0

(a+1)x^2-2a^2x+a^3=0
(a+1)x^2-2a^2x+a^3=0

(a+1)x^2-2a^2x+a^3=0
答:
(a+1)x^2-2a^2x+a^3=0
1)当a+1=0即a=-1时:
-2x-1=0
x=-1/2
2)当a+1≠0即a≠-1时:
x=[2a^2±√(4a^4-4a^4-4a^3)]/(2a+2)
=[a^2±√(-a^3)]/(a+1)
当a>0时,方程无解
当a

若a+1=0即a=-1
-2x-1=0
x=-1/2
若a+1≠0
即a≠-1
△=(-2a^2)^2-4a^3(a+1)=4a^4-4a^4-4a^3=-4a^3
若a>0
则原方程无解
若a≤0
x=[2a^2±√(-4a^3)]/2(a+1)=[a^2±a√(-a)]/(a+1)