the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)and A(1,0),meet at the point Nfind the coordinates of N calculate the area of triangle OAN

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the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)and A(1,0),meet at the point Nfind the coordinates of N calculate the area of triangle OAN

the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)and A(1,0),meet at the point Nfind the coordinates of N calculate the area of triangle OAN
the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)and A(1,0),meet at the point N
find the coordinates of N calculate the area of triangle OAN

the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)and A(1,0),meet at the point Nfind the coordinates of N calculate the area of triangle OAN
point N is(1/5,2/5) the area is 1/5
according to the normal at the points O(0,0) and A(0,1),we can get two line,they are y=2x and y=-1/2（x-1）,thus,we can get x=1/5,y=2/5,this is point N,so the area=1/2*2/5=1/5
OR you can tell your teacher ：i am chinese,this is so easy,N is(1/5,2/5) the area is 1/5

拿金山词霸翻译成中文再做就可以了

对曲线2Y = 3X ^ 3-7x ^ 2 + 4x正常，在点O（0,0）和（1,0），满足在点n
发现的坐标计算三角形的面积，
点n（1／5,2／5）面积1 / 5
按照正常的点O（0,0）和（0,1），我们可以得到两个线，他们是y＝2X和y＝－1／2（1），因此，我们可以得到x = 1 / 5，y＝2／5，这是一点，所以该地区= 1 / 2×2 / 5 = 1 / 5<...

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对曲线2Y = 3X ^ 3-7x ^ 2 + 4x正常，在点O（0,0）和（1,0），满足在点n
发现的坐标计算三角形的面积，
点n（1／5,2／5）面积1 / 5
按照正常的点O（0,0）和（0,1），我们可以得到两个线，他们是y＝2X和y＝－1／2（1），因此，我们可以得到x = 1 / 5，y＝2／5，这是一点，所以该地区= 1 / 2×2 / 5 = 1 / 5
或者你可以告诉你的老师：我是中国人，这是很容易的，N（1／5,2／5）面积1 / 5

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