计算:[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/11 00:10:29
计算:[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]

计算:[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
计算:[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]

计算:[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
=(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)/{1/[x²(x+1)²]}
=(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)*x²*(x+1)²
=-x²/(x-2)