(1)2X^2-5X+1=0 (2)16(X+5)^2-8(X+5)=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 02:13:17
(1)2X^2-5X+1=0 (2)16(X+5)^2-8(X+5)=0

(1)2X^2-5X+1=0 (2)16(X+5)^2-8(X+5)=0
(1)2X^2-5X+1=0 (2)16(X+5)^2-8(X+5)=0

(1)2X^2-5X+1=0 (2)16(X+5)^2-8(X+5)=0
1、
2x²-5x=-1
x²-5x/2=-1/2
x²-5x/2+25/16=-1/2+25/16=17/16
(x-5/4)²=(±√17/4)²
x-5/4±√17/4
x=(5-√17)/4,x=(5+√17)/4
2、
8(x+5)[2(x+5)-1]=0
8(x+5)(2x+9)=0
x=-5,x=-9/2

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 5/x^2+x - 1/x^2-x=0 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值, (2x-2)(x-1)=0 x(x-5)=5x-10 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X matlab解数值分析题p=(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)解为1,2,3……,20取多个非常小的数用软件工具求解方程p(x)+n*x^19=0,并 (x)-2x·x-x-2x+1=0求x的值, x*x+2x+x*x+10x+x*x+25+2x+x*x+1+1+16+x*x+4x*x+9-12x+16x*x+4-16x=30x*x-7x-15 求x,可以只要答案.如图,全是正方形,一个边长为1,一个边长为4,求总面积,你也可以用你的方法.上面那个方程是我列的.5x*X+7X-72=0 已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方,x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√(1/4)-√(1/2) (1)X-3/X-1+X²-2/(x-1)(X-7)=1+x-5/x-7 (2)2x-1/x+4-5=96/x²-16-1-3x/4-x 1、1/2x=2/x+32、x/x+1=(2x/3x+3)+13、2/x-1=4/x²-14、5/x²+x-1/x²-x=0 一元二次方程解答!x(5x+4)=5x+44x^2-45=31x-3x^2+22x-24=0(x+8)(x+1)= -12(3x+2)(x+3)=x+14 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 先化简再求值(x-1/x-x-2/x+1)/(2x²-x/x²+2x+1)且x²-x-1 =0 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) x(x-2)-2x(x+1)-3x(x-5) 其中x=负½ (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)