30分钟,(1)a^2-4/a+2÷(a-2)x1/a-2(2)x^2/x-2-x-2(3)(a+2/x-x+1/x-2)÷x+4/x^2-2x第三题写错了是:{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/14 11:08:41
30分钟,(1)a^2-4/a+2÷(a-2)x1/a-2(2)x^2/x-2-x-2(3)(a+2/x-x+1/x-2)÷x+4/x^2-2x第三题写错了是:{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)

30分钟,(1)a^2-4/a+2÷(a-2)x1/a-2(2)x^2/x-2-x-2(3)(a+2/x-x+1/x-2)÷x+4/x^2-2x第三题写错了是:{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)
30分钟,
(1)a^2-4/a+2÷(a-2)x1/a-2
(2)x^2/x-2-x-2
(3)(a+2/x-x+1/x-2)÷x+4/x^2-2x
第三题写错了是:
{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)

30分钟,(1)a^2-4/a+2÷(a-2)x1/a-2(2)x^2/x-2-x-2(3)(a+2/x-x+1/x-2)÷x+4/x^2-2x第三题写错了是:{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)
(1)、[(a^2-4)/(a+2)]÷[(a-2)x1/(a-2)]
=[(a+2)(a-2)/(a+2)]÷1
=a-2;
(2)、x^2/x-2-x-2=x-2-x-2=-4;
(3)、{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)
=[(x+2)/x-(x+1)/(x-2)]÷(x+4)/(x^2-2x)
=[(x+2)(x-2)-x(x+1)]/(x+4)
=-1.

(1)、[(a^2-4)/(a+2)]÷[(a-2)x1/(a-2)]
=[(a+2)(a-2)/(a+2)]÷1
=a-2;
(2)、x^2/x-2-x-2=x-2-x-2=-4;
(3)、[(a+2)/x-(x+1)/(x-2)]÷(x+4)/(x^2-2x)
=(ax+x-x^2-2a-4)/(x+4)。

你确认你写的题目正确吗,,

是化简吗?

(2)(4x-4)/(x-2)
(3)(-x^2-(a+5)x-2a-4)/(x^3-2x^2)
第一题看不懂

解1题:
原式=2xy/(x²-y²)+x/(x+y)
=2xy/[(x+y)(x-y)]+[x(x-y)]/[(x+y)(x-y)]
=[2xy+x(x-y)]/[(x+y)(x-y)]
=(2xy+x²-xy)/[(x+y)(x-y)]
=(x²+xy)/[(x+y)(x-y)]
=[x(x+y)]/(x+...

全部展开

解1题:
原式=2xy/(x²-y²)+x/(x+y)
=2xy/[(x+y)(x-y)]+[x(x-y)]/[(x+y)(x-y)]
=[2xy+x(x-y)]/[(x+y)(x-y)]
=(2xy+x²-xy)/[(x+y)(x-y)]
=(x²+xy)/[(x+y)(x-y)]
=[x(x+y)]/(x+y)(x-y)]
=x/(x-y)
解2题:
原式=[a²/(a-2)-4/(a-2)]×[1/(a²+2a)]×(a²+2a)
=[(a²-4)/(a-2)]
=[(a+2)(a-2)]/(a-2)
=a+2
解3题:
原式=[1+3/(x-1)]÷[(x+2)/(x²-1)]
=[(x-1+3)/(x-1)]×[(x²-1)/(x+2)]
=[(x+2)/(x-1)]×[(x+1)(x-1)/(x+2)]
=x+1

收起

加上必要的括号啊
1.a-2
2.x^2/-4
3.(a+2)x/(x+4)

(1)、[(a^2-4)/(a+2)]÷[(a-2)x1/(a-2)]
=[(a+2)(a-2)/(a+2)]÷1
=a-2;
(2)、x^2/x-2-x-2=x-2-x-2=-4;
(3)、{1+(2)/(x)-(x+1)/(x-2)}÷(x+4)/(x^2-2x)
=[(x+2)/x-(x+1)/(x-2)]÷(x+4)/(x^2-2x)
=[(x+2)(x-2)-x(x+1)]/(x+4)
=-1。