(x-1)-(x-1)^2+(x-1)^3-(x-1)^4+(x-5)^5的展开式中x^2的系数RT

来源：学生作业帮助网编辑：作业帮时间：2024/05/01 16:37:54

(x-1)-(x-1)^2+(x-1)^3-(x-1)^4+(x-5)^5的展开式中x^2的系数RT
(x-1)-(x-1)^2+(x-1)^3-(x-1)^4+(x-5)^5的展开式中x^2的系数
RT

(x-1)-(x-1)^2+(x-1)^3-(x-1)^4+(x-5)^5的展开式中x^2的系数RT
(x-1)无二次项系数为0
-(x-1)^2 二次项系数为-1
(x-1)^3 二次项系数为-1*C13（1上标 3下标）=-3
-(x-1)^4 二次项系数为-1*(-1)^2*C24（2上标 4下标）=-6
(x-5)^5 二次项系数为(-1)^3*C35（3上标 5下标）=-10
综合即为0-1-3-6-10=-20

原式=-(1-x)-(1-x)^2-(1-x)^3-(1-x)^4-(1-x)^5
所以，x^2的系数等于0-1-3-6-10=-20

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