(1+√3i)³计算

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(1+√3i)³计算

(1+√3i)³计算
(1+√3i)³计算

(1+√3i)³计算
原式=[2(cosπ/3+isinπ/3)]³
=2³[cos(3*π/3)+isin(3*π/3)]
=8(-1+0)
=-8