y=sin(2x+π/3)的单调区间函数y=sin(1/2x+π/3)x∈[-2π,2π]的单调递增区间y=2sin(2x+π/3)在[-π/4,π/4]的取值范围

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 05:19:21
y=sin(2x+π/3)的单调区间函数y=sin(1/2x+π/3)x∈[-2π,2π]的单调递增区间y=2sin(2x+π/3)在[-π/4,π/4]的取值范围

y=sin(2x+π/3)的单调区间函数y=sin(1/2x+π/3)x∈[-2π,2π]的单调递增区间y=2sin(2x+π/3)在[-π/4,π/4]的取值范围
y=sin(2x+π/3)的单调区间
函数y=sin(1/2x+π/3)x∈[-2π,2π]的单调递增区间
y=2sin(2x+π/3)在[-π/4,π/4]的取值范围

y=sin(2x+π/3)的单调区间函数y=sin(1/2x+π/3)x∈[-2π,2π]的单调递增区间y=2sin(2x+π/3)在[-π/4,π/4]的取值范围
利用换元法很简单的,自己动手,丰衣足食.

(1).y=sin(2x+π/3)=>2x+π/3在[-π/2+2kπ,π/2+2kπ]区间内递增,在[π/2+2kπ,3π/2+2kπ]区间内递减
(2).[-5π/3,π/3]
(3).[-1,2]