2a(b-c)²-3b+3c=
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2a(b-c)²-3b+3c=
2a(b-c)²-3b+3c=
2a(b-c)²-3b+3c=
2a(b-c)²-3b+3c
=2a(b-c)²-3(b-c)
=(b-c)[2a(b-c)-3]
=(b-c)(2ab-2ac-3)
2a(b-c)²-3b+3c=
2a(b-c)²-3b+3c=
2a(b-c)²-3b+3c=
2a(b-c)²-3b+3c
=2a(b-c)²-3(b-c)
=(b-c)[2a(b-c)-3]
=(b-c)(2ab-2ac-3)